Question

If x:y=3:4 and y:z=3:4 then
$\frac{x + y + z}{3z} \\ \\is \: equal \: to$
(a)
$\frac{13}{27}$
(b)
$\frac{1}{2}$
(c)
$\frac{73}{84}$
(d)
$\frac{37}{48}$

Answer 1

The answer is (d) 37/48 , Here is the solution, 
By the way, We can solve this in 2 ways, I am giving you only 1 solution, Sorry for that !

Here it is :
Given that,

x/y = 3/4, and similarly y/z = 3/4,

Now, To find the answer, let us convert all the variables into 1 variable, Here I am going to convert every variable in terms of y,

Now,
From the question, We can say that,
x = (3y)/4, and z = (4y)/3 , and y = y,

$\frac{x+y+z}{3z} = \frac{ \frac{3y}{4} +y + \frac{4y}{3} }{4y}$ ,

=> (9y + 12y + 16y)/48y,
=> 37y/48y , Cancelling out the y variable,
=> 37/48,

Therefore the answer is 37/48,

Hope you understand, Have a Great day and Advance Merry Christmas !
Thanking you, Bunti 360 !