Question

If (x + y) = 3 and xy =2 find the value of x^2 + y^2 with full process

Answer 1

Answer:

x+y=3

xy=2

x^2+ y^2

Step-by-step explanation:

Using formula (a+b) whole square

(x+y)^2= x^2+y^2+2xy

(x+y)^2= x^2+y^2 + 2(2)

(3)^2= x^2+y^2+ 4

6-4=x^2+y^2

2= x^2 + y^2

Answer 2

Answer:

x² + y² = 5

Step-by-step explanation:

We have,

x + y = 3

xy = 2

Now, to get x² + y² we must square (x + y)², don't you think!!!

So,

(x + y)² = x² + 2xy + y²

Substituting what we are given,

(3)² = x² + 2(2) + y²

9 = x² + y² + 4

x² + y² = 9 - 4

Thus,

x² + y² = 5

Hope it helped you and believing you understood it....All the best