Question

If x+y=3 and xy = 2, then the value of x^3'-y^3 is equal to :




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Answer 1

Answer:

${x}^{3} - {y}^{3} = (x - y)( {x}^{2} + xy + {y}^{2}$

${x}^{2} + {y}^{2} = ( {x + y)}^{2} - 2yx$

for a change in the given question it's not x+y=3 its x-y=3

and the simplification can be done by u

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