Question

if x-y= 3 and xy=28, find x+y using appropriate identities​

Answer 1

Answer:

(x-y)²=x²+y²-2xy

(3)²=x²+y²-2(28)

9=x²+y²-56

56+9=x²+y²

65=x²+y²

(x+y)²=x²+y²+2xy

(x+y)²=65+2×28

(x+y)²=65+56

x+y=root 121

x+y=11

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Answer 2

Answer:

x=7 and y= 4

7-4=3

7×4=28

Hence x+y =11.

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