Question

If x:y =4:3 find (3x+4y): (5x+6y)

Q please​

Answer 1

Answer:

Put x=3y=4

(3x+4y):(5x+6y)=(3×3+4×4):(5×3+6×4)

=(9+16):(15+24)

=25:39

Answer 2

Answer:

$\frac{12}{19}$

Step-by-step explanation:

Let, x = 4k & y = 3k         [As, x:y =4:3]

:. $\frac{(3x+4y)}{(5x+6y)}$ = $\frac{((3*4k)+(4*3k))}{((5*4k)+(6*3k))}$ = $\frac{12k + 12k}{20k + 18k}$ = $\frac{24k}{38k}$ = $\frac{12}{19}$