if x+y=4 and xy=2 , find the value of x2+y2
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hey mate! here's your answer!
since, x + y = 4 and xy = 2
so, (x + y)² = (4) ²
=> x²+y²+2xy = 16
=> x²+y²+2(2) = 16
=> x²+y² + 4 = 16
=> x²+y² = 16-4
=> x²+y² = 12
hope it is helpful ✌️
since, x + y = 4 and xy = 2
so, (x + y)² = (4) ²
=> x²+y²+2xy = 16
=> x²+y²+2(2) = 16
=> x²+y² + 4 = 16
=> x²+y² = 16-4
=> x²+y² = 12
hope it is helpful ✌️
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