If x - y = 4 and xy = 45 Find the value of x^3 - y^3??
(Need step by step answer plz)
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\left[x _{2}\right] = \left[ - \sqrt[3]{\left( -1\right) }\,\sqrt[3]{y^{3}}\right][x2]=[−3√(−1)3√y3]
Lily200:
I can't understand the ans
Answered by
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Answer:
Step-by-step explanation:
x-y=4
xy=45
(x-y)³=x³-y³-3xy(x-y)
(4)³=x³-y³-3*45*4
64=x³-y³-540
x³-y³=64+540
=604
so, x³-y³=604
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