Question

If x+y=4, y+z=7 and x+z=5 the value of (x+y+z)^2 is.....

Answer 1

x + y = 4 ---1equation
y + z = 7 ---2equation
x + z = 5 ---3equation

××××××××××××××××××××××

Adding all the equations,

x + y = 4
y + z = 7
x + z = 5
____________
2x + 2y + 2z = 16
____________

2x + 2y + 2z = 16

=> 2(x + y + z) = 16

=> x + y + z = 16/2

=> x + y + z = 8


Square on both sides,

=> (x + y + z)² = 8²

=> (x + y + z)² = 64 [your Answr]


I hope this will help you


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