If x-y=4and x^+y^=136 then xy=?
Answers
Answered by
0
Answer:
By using (x-y) ^2=x^2+y^2-2xy
Hope it helps!
Attachments:
Answered by
0
x^2 + y^2=136
x^2 + y^2=136x-y=4
x^2 + y^2=136x-y=4x^2 + y^2= (x-y)^2+2xy
x^2 + y^2=136x-y=4x^2 + y^2= (x-y)^2+2xy136=16+2xy
x^2 + y^2=136x-y=4x^2 + y^2= (x-y)^2+2xy136=16+2xy2xy=120
x^2 + y^2=136x-y=4x^2 + y^2= (x-y)^2+2xy136=16+2xy2xy=120so,xy= 60
Similar questions