Math, asked by vishal565, 1 year ago

If x—y=4and x y=21, then x³ —y³

Answers

Answered by Ammchu
0
x³-y³= (x-y) (x²+xy+y²)
= 4(x²+y²+21)..... eq 1
y= 21/x
x-21/x=4
x² - 21 - 4x = 0
x= - 7 or x= 4
Here, x= - 7 is valid. y= -3
Eq 1,
Req. ans: = 4( 49+9+21)
=316
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