if x+y=5 and xy=6 ,find the value of x^3+y^3
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manpreetcheema23:
please tell me the answer
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Answered by
7
Hey mate,
We will express x in terms of y,
x = 6/y... (1)
Put (1)
In first equation,
6/y + y = 5
6+y^2 = 5y
Now we will rearrange terms and solve the upcoming quadratic equation,
y^2 - 5y +6 = 0
y^2 - 2y - 3 y +6 = 0
y(y-2) - 3(y-2) = 0
So y = 2, 3
Then x from(1)
= 3,2
Then required answers,
= 3^3 + 2^3
= 27 + 8
= 35
Note :- the answer will come same in both the cases.
So your answer is 35
Hope this helps you out!
We will express x in terms of y,
x = 6/y... (1)
Put (1)
In first equation,
6/y + y = 5
6+y^2 = 5y
Now we will rearrange terms and solve the upcoming quadratic equation,
y^2 - 5y +6 = 0
y^2 - 2y - 3 y +6 = 0
y(y-2) - 3(y-2) = 0
So y = 2, 3
Then x from(1)
= 3,2
Then required answers,
= 3^3 + 2^3
= 27 + 8
= 35
Note :- the answer will come same in both the cases.
So your answer is 35
Hope this helps you out!
Answered by
0
the answer is.....x^3+y^3=35
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