if x+y=5 and xy =6 then find x³+y³
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Answered by
41
Hi friend!!
Given, x+y=5--------(1)
Squaring on both sides, we get
x²+y²+2xy=25
Given, xy=6-----(2)
→x²+y²+2(6)=25
x²+y²+12=25
x²+y²=13--------(3)
Now, x³+y³=(x+y)(x²+y²-xy)
From (1),(2),(3) we get
x³+y³=5(13-6)
=5(7)=35
I hope this will help you ;)
Given, x+y=5--------(1)
Squaring on both sides, we get
x²+y²+2xy=25
Given, xy=6-----(2)
→x²+y²+2(6)=25
x²+y²+12=25
x²+y²=13--------(3)
Now, x³+y³=(x+y)(x²+y²-xy)
From (1),(2),(3) we get
x³+y³=5(13-6)
=5(7)=35
I hope this will help you ;)
sowmiyayahoocom:
hey dhanya can u help me with my sum
Answered by
10
Hii friend!!
x^3 + y^3 = (x +y) ( x^2 + y^2 -xy )
= (5) ( 5^2 - 6 )
= 5 ( 25 -6 )
= 5× 19
= 95
Hope it will help you
x^3 + y^3 = (x +y) ( x^2 + y^2 -xy )
= (5) ( 5^2 - 6 )
= 5 ( 25 -6 )
= 5× 19
= 95
Hope it will help you
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