If x+y=5 and xy=6 then x3+y3=?
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apply identity
(x+y)3=x3+y3+3xy(x+y)
(5)3=x3+y3+3×6(5)
125=x3+y3+18×5
125-90=x3+y3
35=x3+y3
apply identity
(x+y)3=x3+y3+3xy(x+y)
(5)3=x3+y3+3×6(5)
125=x3+y3+18×5
125-90=x3+y3
35=x3+y3
SJking1:
hi
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