Math, asked by jainlakshita, 9 months ago

If x-y = 5 and xy = 7 find the value of x^3-y^3​

Answers

Answered by rohitsgh95
0

Step-by-step explanation:

x {}^{3 }  - y {}^{3}  = (x - y) {}^{3}   + 3xy(x - y)

now put the value of (x-y) and xy in above formula.

x {}^{3 } - y {}^{3}  = 5 {}^{3}  + 3 \times 7 \times 5 \\  = 25 + 105 \\  x {}^{3}   - y {}^{3}  = 130

Answered by SUZEM
0

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