Math, asked by jeet07abhi29, 8 months ago

x+2y+2=0 3x+2y-2=0 by cross multiplication method

Answers

Answered by shyamaldebbarma2020
0

Answer:

Solve by Substitution

Let's solve your system by substitution.

x+2y+2=0;3x+2y−2=0

Step: Solvex+2y+2=0for x:

x+2y+2=0

x+2y+2+−2y=0+−2y(Add -2y to both sides)

x+2=−2y

x+2+−2=−2y+−2(Add -2 to both sides)

x=−2y−2

Step: Substitute−2y−2forxin3x+2y−2=0:

3x+2y−2=0

3(−2y−2)+2y−2=0

−4y−8=0(Simplify both sides of the equation)

−4y−8+8=0+8(Add 8 to both sides)

−4y=8

−4y

−4

=

8

−4

(Divide both sides by -4)

y=−2

Step: Substitute−2foryinx=−2y−2:

x=−2y−2

x=(−2)(−2)−2

x=2(Simplify both sides of the equation)

Answer:

x=2 and y=−2

Answered by deepikasrinallusamy
0

Answer:

x=2;y=-2

Step-by-step explanation:

the answer have been in the image.

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