Math, asked by sapnamarval, 8 months ago

if x-y =5 and xy=8 find the value of x^3-y^3​

Answers

Answered by harshkumarverma481
2

Answer:

5x²+5y²+40

Step-by-step explanation:

x³-y³

Using identities,

a³–b³= (a–b) (a²+ab+b²)

(x-y)(x²+y²+xy)

put (x-y)=5 and xy=8

(5)(x²+y²+8)

5x²+5y²+40

Answered by Anonymous
0

Answer:

heyyy ur ans is here ..

5x^2 +5y^2 + 40

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