if x-y=5 and xy=84 find the value of x cube - y cube
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Hii Ridhi,
Here, x-y=5 => (x-y)^2 =25
=> x^2+y^2-2xy=25
=> x^2+y^2+xy = 25+3xy
=> x^2+y^2+xy= 25 +3×84 = 277
Hence, x^3-y^3 = (x-y)(x^2+y^2+xy)= 5×277 = 1385 ans..
Thank you! !
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