If x+y= 5 ,xy = 10 ..Find x2 + y2
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Answered by
2
Answer:
Given: x+y=5,and xy=10
so,
(x+y)^2=x^2+y^2+2xy
(5)^2=x^2+y^2+2×10.
25=x^2+y^2+20
25-20=x^2+y^2
5=x^2+y^2
Answered by
1
Given that: x−y=3 And xy = 10
Using the given identity: (a−b)2 = a2−2ab+b2
So, (x−y)2 = x2−2xy+y2
⇒ (x−y)2 = x2−2(10)+y2
⇒ (3)2 = x2−20+y2
⇒ 9 = x2+y2−20
⇒ 9+20 =x2+y2
⇒ x2+y2 = 29
The correct answer is x2+y2=29
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