Question

In the following figure, triangle ABC is similar to triangle DEC. If AB = 12, DE = 3, BC = 16, then CD will be: ?​

Answer 1

Answer:

CD = 5

Step-by-step explanation:

When ΔABC ≈ ΔDEC

Find AC by Pythagoras Theorem

$(AC)^{2} = (AB)^{2} + (BC)^{2}$

$(AC)^{2} = (12)^{2} + (16)^{2} \\(AC)^{2} = 144 + 256\\(AC)^{2} = 400\\AC = \sqrt{400}$

∴ AC = 20

$\frac{AB}{DE}$ = $\frac{BC}{CE}$ = $\frac{AC}{CD}$

$\frac{12}{3} = \frac{20}{CD} \\\\CD = \frac{60}{12} \\CD = 5$

Answer 2

Answer:

the figru is triangle so the

CD will be

=145