Question

If x-y=6 and xy=8,find the value if x*x+y*y.​

Answer 1

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Given,

$x - y = 6$

$xy = 8$

To find value of =

${x}^{2} + {y}^{2}$

By squaring x-y = 6

${(x - y)}^{2} = {(6)}^{2}$

Using the identity,

${a}^{2} - 2ab + {b}^{2}$

${x}^{2} + {y}^{2} = 36 + 2(xy)$

${x}^{2} + {y}^{2} = 36 + 16$

∴

${x}^{2} + {y}^{2} = 52$

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