if x+y=6and xy=11, find the value of x^3+y^3
Answers
Answered by
0
Answer:
Correct option is
A
−288
x−y=−6,xy=4
(x−y)
3
=x
3
−y
3
−3x
2
y+3xy
2
=−216
=x
3
−y
3
−3yx(x−y)=−216
x
3
−y
3
=−216+3(4)(−6)
x
3
−y
3
=−288
Was this answer helpful?
Answered by
0
i think the above answer is wrong. it can be solve by using the formula
Similar questions