If x+ y = 7/2 and xy = 5/2, find i) (x-y) ii) x2-y2
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Answer:
x+y = 7/2
So, (x+y)^2 = (7/2)^2
So, x^2 + 2xy + y^2 = 49/4
So, x^2 + y^2 = 49/4 - 2xy = 49/4 - 2*5/2
So, x^2 + y^2 = 29/4
Now, (x-y)^2 = x^2 + y^2 - 2xy
So, (x-y)^2 = 29/4 - 2*5/2
So, (x-y)^2 = 9/4
Therefore, x-y = Sq. Root of 9/4 = +3/2 or -3/2
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