If x+y = 7 & XY = 12, find x^ 2 + y ^2.
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Answered by
1
Answer:
hi
your answer is
25
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Answered by
0
Answer:
★
x + y = 12
xy = 14
Now find the value of x² + y² .
→ x² + y²
Use identity : a²+b² = (a+b)² - 2ab
→ (x+y)² - 2xy
Put values : x+y = 12 and xy = 14
→(12)² - 2×14
→ 144 - 28
→ 116 [ Answer ]
__________________
★
x-y = 7
xy = 9
Now find the value of x²+y² .
→ x² + y²
Use identity : a²+b² = (a-b)² + 2ab
→ (x+y)² - 2xy
Put values : x-y = 7 and xy = 9
→(7)² + 2×9
→ 49 + 18
→ 67 [ Answer ]
__________________
Some identities :-
★ (a+b)² = a² + 2ab + b²
★ (a-b)² = a² - 2ab + b²
★ a² - b² = (a+b) (a-b)
★ a²+b² = (a-b)² + 2ab
★ a²+b² = (a+b)² - 2ab
Step-by-step explanation:
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