If x+y = 7 and xy=11 what is the value of x-y
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Answer:
Given:
• x+y=7
• xy=11
• x-y=?
As we know
• (x+y{)}^2 - (x-y{)}^2 = 4xy(x+y)2−(x−y)2=4xy
Putting the values
• (7{)}^2 - (x-y{)}^2 = 4(11)(7)2−(x−y)2=4(11)
• 49 - (x-y{)}^2 = 4449−(x−y)2=44
• - (x-y{)}^2 = 44 - 49−(x−y)2=44−49
• - (x-y{)}^2 = - 5−(x−y)2=−5
Cancellation of Minus
• (x-y{)}^2 = 5(x−y)2=5
Taking square root both hand sides
\sqrt{(x-y{)}^2} = \sqrt{5}(x−y)2=5
• (x-y) = 5(x−y)=5
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