Question

if (x-y) = 7 find(X-15)*3-(y-8)*3 please send it fastly it's very very very urgent​

Answer 1

Given: x-y =7 => x-y-7=0 —(1)

We know :

(a^3 - b^3)= (a - b)(a^2+ab+b^2)

To find the value of (x-15)^3-(y-8)^3

Let a = x-15, b = y-8

(x-15)^3-(y-8)^3 = ((x-15)-(y-8))((x-15)^2+(x-15)(y-8)+(y-8)^2)

RHS:

(x-y-7)((x-15)^2+(x-15)(y-8)+(y-8)^2)

From equation (1)

(0)((x-15)^2+(x-15)(y-8)+(y-8)^2)

0

So, the solution is zero