If x+y =8 & x-y=2, find the value of 2x^2+2y^2
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Answer:
X+y=8
(x+y)=8^2=64
x-y=2
(x-y)^2=4
2x^2+2y^2
=2(x^2+y^2)
=(x+y)^2+(x-y)^2
=(64+4)
=68(ans)
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