Question

if x+y =9 and xy = 16,find the value of (x^2+y^2).​

Answer 1

Answer:

Hey mate, Good morning ♡

#Here's ur answer ☆☆☆

Step-by-step explanation:

$x + y = 9 \\ squaring \: both \: sides \\ (x + y) {}^{2} = 81 \\ x {}^{2} + 2xy + y {}^{2} = 81 \\ xy \: given \: = 16 \\ x {}^{2} + 2 \times 16 + y {}^{2} = 81 \\ x {}^{2} + y {}^{2} = 81 - 32 = 49(ans)$

hope this helps you....

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Answer 2

Answer:

49

Step-by-step explanation:

we know that,

(x + y)^2 = x^2 + 2×x×y + y^2

(9)^2=2×16+ x^2 + y^2

81-32 = x^2 + y^2

x^2 +y^2= 49