Math, asked by rv160405, 1 month ago

If x^y= e^x-y then dy/dx =​

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Answered by captainofstudy
0

Answer:

If x^y=e^(x-y), show that dy/dx=logx/{log(xe)}^2. If xy=e(x-y), show that dy/dx=logx/{log(xe)}2.16

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