if X + y is equals to 8 and x y is equals to 3 find the value of 3 ( X² + y²)
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x+y =8
x+y =8xy= 3
x+y =8xy= 3(x+y)²= x²+2xy+y²
x+y =8xy= 3(x+y)²= x²+2xy+y² 8² = x²+ y² + 2 (3)
x+y =8xy= 3(x+y)²= x²+2xy+y² 8² = x²+ y² + 2 (3) 64= _____+ 6
x+y =8xy= 3(x+y)²= x²+2xy+y² 8² = x²+ y² + 2 (3) 64= _____+ 6x²+ y² = 58
x+y =8xy= 3(x+y)²= x²+2xy+y² 8² = x²+ y² + 2 (3) 64= _____+ 6x²+ y² = 58So, 3(x²+y²)= 3×58 = 174
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