What's two numbers total 40 and have a difference of 8
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Answer:
32,+8
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24,16
Step-by-step explanation:
Let one number be X and another y.
GIVEN: x+y=40 (equation 1......)
x-y=8 (equation 2....)
NOW SOLVE EQUATION 2 FOR x TO GET REVISED EQUATION 2: x-y=8
x=8+y
Then substitute x in equation 1 from revised equation 2 and then solve for y.
x+y=40
8+y+y=40
8+2y=40
2y=40-8=32
y=16
Therefore y for 16 in equation 1 and solve for X:
x+y=40
X+16=40
X=40-16=24
PROOF:SUM=24+16=40
DIFFERENCE=24-16=8
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