Question

if (x/y)+(y/x)=1 then find value of
x^3-y^3​

Answer 1

Answer:

x/y+y/x=1

take l.c.m.

$\frac{x^{2}+y^{2}}{xy} = 1$

cross multiply

$x^{2} +y^{2} =xy$

$x^{2} +y^{2} -xy=0 ----------(1)\\now\\x^{3} -y^{3}= (x-y)[x^{2} +y^{2} -xy]\\from (1)\\x^{3} -y^{3}= (x-y)(0) \\x^{3} -y^{3}=0$

${(x+y)}^2 +2xy = xy$

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