if x/y +y/x =-1 when x ≠0 then find the value of x³-y³
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5
Answer:
0
Explanation:
We know that,x3 - y3 = (x - y)(x² + xy + y²) ....(i)
Given that, x/y + y/x = -1
(x² + y²)/xy = -1
x² + y² = -xy
x² + y² + xy = 0
(x² + xy + y²) = 0
Multyplying by (x - y) on both sides we get,(x - y)(x² + xy + y²) = (x - y) × 0
x3 - y3 = 0 using (i)
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