if x/y+y/x=1(x,y equalnot 0,the value of x^3+y^3 is
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X/Y +Y/X=1
X^2+Y^2/XY=1
X^2+Y^2=XY
X^2+Y^2-XY=0. (1)
X^3+Y^3=(x+y)(x^2+y^2-xy)
=0. [by eq.(1)]
X^2+Y^2/XY=1
X^2+Y^2=XY
X^2+Y^2-XY=0. (1)
X^3+Y^3=(x+y)(x^2+y^2-xy)
=0. [by eq.(1)]
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Answer:
x^3 + y^3 = 0
Step-by-step explanation:
Given: x/y + y/x = 1
Find: x^3 + y^3
Solution:
x/y + y/x = 1
(x^2 + y^2)/(xy) = 1
x^2 + y^2 = xy
x^2 + y^2 - xy = 0 ----(1)
x^3 + y^3 = (x+y)(x^2 + y^2 - xy)
x^3 + y^3 = (x+y)(0)
x^3 + y^3 = 0 ----from(1)
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