Math, asked by nikhilverma01, 1 year ago

if x/y+y/x=1(x,y equalnot 0,the value of x^3+y^3 is​

Answers

Answered by agXaa
0
X/Y +Y/X=1
X^2+Y^2/XY=1
X^2+Y^2=XY
X^2+Y^2-XY=0. (1)

X^3+Y^3=(x+y)(x^2+y^2-xy)
=0. [by eq.(1)]

Answered by Anonymous
3

Answer:

x^3 + y^3 = 0

Step-by-step explanation:

Given: x/y + y/x = 1

Find: x^3 + y^3

Solution:

x/y + y/x = 1

(x^2 + y^2)/(xy) = 1

x^2 + y^2 = xy

x^2 + y^2 - xy = 0 ----(1)

x^3 + y^3 = (x+y)(x^2 + y^2 - xy)

x^3 + y^3 = (x+y)(0)

x^3 + y^3 = 0 ----from(1)

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