if x/y+y/x=-1 , x , y is not equal to 0 then the value of x3 - y 3 is
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Step-by-step explanation:
Here,
x/y + y/x = - 1
⇒ ( x² + y² ) /xy = - 1
⇒ x² + y² = - xy
We know, a³ - b³ = ( a - b )( a² + ab + b² )
Here,
⇒ x³ - y³
⇒ ( x - y )( x² + xy + y² )
⇒ ( x - y )( x² + y² + xy )
From above, x² + y² = - xy
⇒ ( x - y )( - xy + xy )
⇒ ( x - y )( 0 )
⇒ 0
Hence x³ - y³ = 0
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