Question

If x+y,y+z,z+x are in the ratio 6:7:8 and x+y+z =14 then the value of x is

Answer 1

Answer:

$\frac{14}{3}$

Step-by-step explanation:

let x+y = 6p (1) then y+z=7p. (2) , z+x=8p (3)

Sum all of it

2(x+y+z) = 21p

21p = 28 or p = 4/3

Subtract eq 1 from 2 and add in 3

2x = 7p

$x = \frac{7p}{2} = \frac{7}{2} \times \frac{4}{3} = \frac{14}{3}$