Math, asked by prishabbhatt, 9 months ago

pls answer it!!
its emergency..​

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Answers

Answered by surenderkumar72684
1

Answer:

= 4500 tiles

Step-by-step explanation:

base of tile = 24 cm

height of tile = 10 cm

area of tile shape of parallelogram = b×h

= 24 × 10

= 240cm^2

change cm into m

= 240/100

= 0.24m

no. of tiles required to cover floor of area 1080m^2 = 1080/0.24

= 4500 tiles

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Answered by Anonymous
14

ANSWER:-

Given:

•A flooring tiles the shape of a parallelogram whose base is 24cm.

•The corresponding height is 10cm.

To find:

How many such tiles required to cover a floor of area 1080m².

Solution:

Firstly we convert in metres:

Base: 24/100 = 0.24m

Height: 10/100 = 0.1m

According to the question:

We know area of parallelogram;

=) Base × height

Area of tiles:

=) 0.24m × 0.1m

=) 0.024m²

Therefore,

•Area of the floor= 1080m²

Now,

Number of tiles:

 =  >  \frac{Total \: area}{Area \: of \: one \:tiles}  \\  \\  =  >  \frac{1080}{0.024}  \\  \\  =  >  \frac{1080 \times 1000}{0.024 \times 1000}  \\  \\  =  >  \frac{1080000}{24}  \\  \\  =  > 45000 \: tiles

Hence,

45000 tiles required to cover a floor.

Thank you.

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