If x+y+z = 0 and x 2 +y 2 +z 2 = 12 find the value of xy+yz+zx. And please no links or similar questions.
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Since, (x+y+z)² = x²+y²+z²+2(xy+yz+zx)
according to the question,
(0) = 12 + 2(xy+yz+zx)
∴ xy + yz + zx = -6
according to the question,
(0) = 12 + 2(xy+yz+zx)
∴ xy + yz + zx = -6
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