if X + Y + Z =0 show that X^3 + Y^3 + Z^3= 3 xyZ (without the help of the formula)
Answers
Answered by
2
Hello Mate!
x^3 + y^3 + z^3 - 3xyz = ( x + y + z )( x^2 + y^2 + z^2 - xy - yz - xz )
Now, as x + y + z = 0
x^3 + y^3 + z^3 - 3xyz = 0 ( x^2 + y^2 + z^2 - xy - yz - xz )
x^3 + y^3 + z^3 = 3xyz
Hope it helps☺!✌
x^3 + y^3 + z^3 - 3xyz = ( x + y + z )( x^2 + y^2 + z^2 - xy - yz - xz )
Now, as x + y + z = 0
x^3 + y^3 + z^3 - 3xyz = 0 ( x^2 + y^2 + z^2 - xy - yz - xz )
x^3 + y^3 + z^3 = 3xyz
Hope it helps☺!✌
kritabhi:
ok
Similar questions