Question

If x + y + z = 0 show that x^3 + y^3 + z^3= 3xyz

Answer 1

x+y+z = 0

=> x+y = - z --------(1)

On cubing both sides, we get

x^3 +y^3 +3xy(x+y) = - z^3

=> x^3 +y^3 +3xy(-z) = - z^3

=> x^3 +y^3 - 3xyz = - z^3

=> x^3 +y^3 +z^3 = 3xyz

Answer 2

This wrong answer is 3 rase two pawer3 and xyz