Question

If X+y+z=0, then find 1/(x^2+z^2-y^2) + 1/(y^2+z^2-x^2) + 1/(y^2+x^2-z^2)

Answer 1

Answer:

$given \\ x + y + z = 0 \\ now \\ \frac{1}{ {x}^{2} + {z}^{2} - {y}^{2} } + \frac{1}{ {y}^{2} + {z}^{2} - {x}^{2} } + \frac{1}{ {y}^{2} + {x}^{2} - {z}^{2} } \\ \frac{1}{(x + z + y)(x + z - y)} + \frac{1}{(y + z + x)(y + z - x)} + \frac{1}{(y + x + z)(y + x - z)} \\ \frac{1}{0(x + z - y)} + \frac{1}{0(y + z - x)} + \frac{1}{0(y + x - z)} \\ \frac{1}{0} + \frac{1}{0} + \frac{1}{0} \\ 0 + 0 + 0 = 0 \\ anssssssss$

Step-by-step explanation:

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