Question

if x+y+z=0 then prove that x^3+y^3+z^3=0.

Answer 1

The question is 100% incorrect.

Answer 2

$x {3}^{} + y {3}^{} + z {3}^{} \\ =( x + y + z)(x {}^{2} + y {}^{2} + z {}^{2} - xy - yz - z x \\ = 0 \times( x {}^{2} + y {}^{2} + z {}^{2} - xy - yz - zx) \\ = 0(ans)$
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