Question

If x+y+z=0 then,prove that x³+y³+z³=3xyz​

Answer 1

Answer:

Step-by-step explanation:

X+y+z=0

Answer 2

x+y+Z=0
x+y=-z
cubing both side
(x+y)cube= (-z)cube
x cube +y cube +3xy(x+y)= -z cube
x cube +y cube + 3xy × -z =-z cube
x cube + y cube -3xyz = -z cube
x cube + y cube + Z cube = 3xyz....



proved