if x+y+z = 0 then x^3+y^3+z^3
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0
Answer:
if x+y+z = 0
then ,
x^3+y^3+z^3 = 3xyz
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Answered by
1
Answer:
x+y+z = 0
Prove that : x^3+y^3+z^3 - 3xyz
Step-by-step explanation:
We know that
x^3+ y^3+ z^3 - 3xyz
= (x + y + z) (x^2 + y^2 + z^2 - xy - yz - zx)
Using identity
(0) (x^2 + y^2 + z^2 - xy - yz - zx)
because x + y + z = 0
= 0
=> x^3 + y^3 + z^3 = 3xyz
Hope this answer will help you...
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