Question

pls solve it .. if u can ​

Answer 1

Answer:

Q8-C

Q9-D

Q10-C

Q11-C

Q12-D HINT(We know that, the perpendicular distance of a point from the X-axis gives y-coordinate of that point. Here, foot of perpendicular lies on the negative direction of X-axis, so perpendicular distance can be meausre in II quadrant or III quadrant . Hence , the point P has y-coordinate =5 or -5.)

Q13-B HINT(Here, point 0(0,0) is the origin. A(3,0) lies on positive direction of X-axis , B(3,4) lies in Ist quadrant and C(0,4) lines on positive direction of Y-axis . On joining 0A,AB,BC nd C0 the figure obtained is a rectangle.)

Q14-B

Q15-B HINT(Here the given points are

P(2,3)⟶abscissa is 2and

Q(3,5)⟶abscissa is 3.

∴difference between the abscissaeis

∣2−3∣=1)

MARK BRAINLIEST,

HOPE YOUR DOUBTS ARE CLEAR