Question

if x+y+z=0 then x^3+y^3+z^3=3xyz

Answer 1

here is your answer

hope it helps u

Answer 2

Step-by-step explanation:

if x+y+z=0then if we can write it as

x+y=-z

and cube on both the sides

so

(x+y)³=-z³

so (a+b)³=a³+b³+3ab(a+b)

so

x³+y³+3xy(x+y)=-z³

and x+y=-z(already stated)

so x³+y³+3xy(-z)=-z³

x³+y³-3xyz=-z³

so it'll be

x³+y³+z³=3xy

finally proved the above question

hence it's done

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