If x+y+z = 0 then x cube + y cube + z cube = 3xyz
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Answer:
true
Step-by-step explanation:
x+y+z=0,
x+y=-z,
cubing on both sides,
(x+y)³=(-z)³,
x³+y³+3xy(x+y)=-z³,{since x+y=-z},
x³+y³-3xyz+z³=0,
x³+y³+z³=3xyz
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