Question

if x+y+z=0 then (x+y-z)³+(z+x-y)³+(y+z-x)³​

Answer 1

Step-by-step explanation:

$x + y + z = 0 - (i) \\\blue{\mathfrak{\underline{\large{By \: equation \: (i)}}}:} \\ (x+y-z)³+(z+x-y)³+(y+z-x)³ \\ = ( - z-z)³+( - y-y)³+( - x-x)³ \\ = ( - 2z)³+( - 2y)³+( - 2x)³ \\ = - {8z}^{3} - {8y}^{3} - {8x}^{3} \\ = - 8( {x}^{3} + {y}^{3} + {z}^{3} ) \\ \\ \red{\mathfrak{\underline{\large{Hope \: It \: Helps \: You }}}} \\ \blue{\mathfrak{\underline{\large{Mark \: Me \: Brainliest}}}}$