Question

if x+y+z=0 then x³+y³+z³=3xyz. true or false​

Answer 1

Answer:

true love you

Answer 2

Answer:

solve by using suitable identities:(2a-3b)³

Step-by-step explanation:

We need to expand (2a−3b)

3

We know suitable identity is (x−y)

3

=x

3

−3x

2

y+3xy

2

+y

3

Here x=2a and y=3b

Therefore, value of (2a−3b)

3

is

=(2a)

3

−3(2a)

2

(3b)+3(2a)(3b)

2

−(3b)

3

=8a

3

−36a

2

b+54ab

2

−27b

3