Math, asked by kesarapuprasad7503, 4 months ago

If x+y+z=0show that x² + y³+z³=3×yx

Answers

Answered by Salmonpanna2022
2

Step-by-step explanation:

Given:

If x+y+z=0show that x³+ y³+z³=3xyx

Solution:

If x+y+z=0show that x² + y³+z³=3×yx

Proof: °.° x³+y³+z³-3xy=(x+y+z)(x²+y²+z²-xy-yx-zx)

= 0 [°.° x+y+z=0(Given)]

=> x³+y³+z³-3xyz=0

.°. x³+y³+z³ = 3xyz

So,we have the following conditional identify:

| If x+y+z=0,then ++=3xyx |

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