If x+y+z=0show that x² + y³+z³=3×yx
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Step-by-step explanation:
Given:
If x+y+z=0show that x³+ y³+z³=3xyx
Solution:
If x+y+z=0show that x² + y³+z³=3×yx
Proof: °.° x³+y³+z³-3xy=(x+y+z)(x²+y²+z²-xy-yx-zx)
= 0 [°.° x+y+z=0(Given)]
=> x³+y³+z³-3xyz=0
.°. x³+y³+z³ = 3xyz
So,we have the following conditional identify:
| If x+y+z=0,then x³+y³+z³=3xyx |
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