Question

if X+y+z =1 ,ax+by+cz=k , a²x+b²y+c²z=k² has unique solution then X=?​

Answer 1

Answer:

(1) x + y + z = 1

⇢x + y + z + -y = 1 + -y

⇢ x + z = -y + 1

⇢ x + z + -z = -y + 1 + -z

(2) ax + by + cz = k

⇢ ax + by + cz + -by = k + -by

⇢ ax + cz = -by + k

⇢ ax + cz + -cz = -by + k + -cz

⇢ ax = -by - cz + k

⇢ ax + cz + -cz = -by + k + -cz

⇢ ax = -by - cz + k

⇢ ax/x = -by - cz + k/x

⇢ a = -by - cz + k/x

(3) a² x + b² y + c² z = k²

• Refer the attachment.